0.1x^2+5x+22.5=0

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Solution for 0.1x^2+5x+22.5=0 equation:



0.1x^2+5x+22.5=0
a = 0.1; b = 5; c = +22.5;
Δ = b2-4ac
Δ = 52-4·0.1·22.5
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-4}{2*0.1}=\frac{-9}{0.2} =-45 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+4}{2*0.1}=\frac{-1}{0.2} =-5 $

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